对于简单JSON的encode是这样的:
if bs, err := json.Marshal(m);
err != nil {
panic(err)
}如何解析比较复杂的JSON串呢?笔者找了一个代码demo,希望通过demo说清楚go是如何解析的。
package main
import "fmt"
import "encoding/json"
type MxRecords struct {
Value string
Ttl int
Priority int
HostName string
}
type Data struct {
MxRecords []MxRecords
}
type Response struct {
Status string `json:"status"`
Data Data `json:"data"`
}
type apiR struct {
Response Response `json:"response"`
}
func main() {
body := `{
"response":
{
"status":"SUCCESS",
"data":
{
"mxRecords":
[
{
"value":"us2.mx3.mailhostbox.com.",
"ttl":1,
"priority":100,
"hostName":"hostname@"
},
{
"value":"us2.mx1.mailhostbox.com.",
"ttl":1,
"priority":100, "hostName":"hostnam233e@"
},
{
"value":"us2.mx2.mailhostbox.com.",
"ttl":1,
"priority":100,
"hostName":"@"
},
],
"cnameRecords":
[
{
"aliasHost":"pop.a.co.uk.",
"canonicalHost":"us2.pop.mailhostbox.com."},
{
"aliasHost":"webmail.a.co.uk.",
"canonicalHost":"us2.webmail.mailhostbox.com."
},
{
"aliasHost":"smtp.a.co.uk.", "canonicalHost":"us2.smtp.mailhostbox.com."
},
{
"aliasHost":"imap.a.co.uk.",
"canonicalHost":"us2.imap.mailhostbox.com."
},
],
"dkimTxtRecord":
{
"domainname":"20a19._domainkey.a.co.uk",
"value":"\"v=DKIM1; g=*; k=rsa; p=DkfbhO8Oyy0E1WyUWwIDAQAB\"",
"ttl":1
},
"spfTxtRecord":
{
"domainname":"a.co.uk",
"value":"\"v=spf1 redirect=_spf.mailhostbox.com\"",
"ttl":1
},
"loginUrl":"us2.cp.mailhostbox.com"
}
}
}`
var r apiR
err := json.Unmarshal([]byte(body), &r)
if err != nil {
fmt.Printf("err was %v", err)
}
// 表示json转换成struct之后的内部某块值
fmt.Println(r.Response.Data.MxRecords[1].HostName)
}根据以上代码来看，解析json的思路就是先根据json的实际情况，先定义struct，之后再逐层的根据内部数据类型来处理。
