对于简单JSON的encode是这样的:
if bs, err := json.Marshal(m); err != nil { panic(err) }
如何解析比较复杂的JSON串呢?笔者找了一个代码demo,希望通过demo说清楚go是如何解析的。
package main import "fmt" import "encoding/json" type MxRecords struct { Value string Ttl int Priority int HostName string } type Data struct { MxRecords []MxRecords } type Response struct { Status string `json:"status"` Data Data `json:"data"` } type apiR struct { Response Response `json:"response"` } func main() { body := `{ "response": { "status":"SUCCESS", "data": { "mxRecords": [ { "value":"us2.mx3.mailhostbox.com.", "ttl":1, "priority":100, "hostName":"hostname@" }, { "value":"us2.mx1.mailhostbox.com.", "ttl":1, "priority":100, "hostName":"hostnam233e@" }, { "value":"us2.mx2.mailhostbox.com.", "ttl":1, "priority":100, "hostName":"@" }, ], "cnameRecords": [ { "aliasHost":"pop.a.co.uk.", "canonicalHost":"us2.pop.mailhostbox.com."}, { "aliasHost":"webmail.a.co.uk.", "canonicalHost":"us2.webmail.mailhostbox.com." }, { "aliasHost":"smtp.a.co.uk.", "canonicalHost":"us2.smtp.mailhostbox.com." }, { "aliasHost":"imap.a.co.uk.", "canonicalHost":"us2.imap.mailhostbox.com." }, ], "dkimTxtRecord": { "domainname":"20a19._domainkey.a.co.uk", "value":"\"v=DKIM1; g=*; k=rsa; p=DkfbhO8Oyy0E1WyUWwIDAQAB\"", "ttl":1 }, "spfTxtRecord": { "domainname":"a.co.uk", "value":"\"v=spf1 redirect=_spf.mailhostbox.com\"", "ttl":1 }, "loginUrl":"us2.cp.mailhostbox.com" } } }` var r apiR err := json.Unmarshal([]byte(body), &r) if err != nil { fmt.Printf("err was %v", err) } // 表示json转换成struct之后的内部某块值 fmt.Println(r.Response.Data.MxRecords[1].HostName) }
根据以上代码来看,解析json的思路就是先根据json的实际情况,先定义struct,之后再逐层的根据内部数据类型来处理。